(3x^2+7x-20)/(x+5)

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Solution for (3x^2+7x-20)/(x+5) equation: 


D( x )

x+5 = 0

x+5 = 0

x+5 = 0

x+5 = 0 // - 5

x = -5

x in (-oo:-5) U (-5:+oo)

(3*x^2+7*x-20)/(x+5) = 0

3*x^2+7*x-20 = 0

3*x^2+7*x-20 = 0

DELTA = 7^2-(-20*3*4)

DELTA = 289

DELTA > 0

x = (289^(1/2)-7)/(2*3) or x = (-289^(1/2)-7)/(2*3)

x = 5/3 or x = -4

(x+4)*(x-5/3) = 0

((x+4)*(x-5/3))/(x+5) = 0

( x+4 )

x+4 = 0 // - 4

x = -4

( x-5/3 )

x-5/3 = 0 // + 5/3

x = 5/3

x in { -4, 5/3 }

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